We are given that \( v \) is a positive multiple of 5, and \( v^2 < 600 \).
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- P = \frac{\text{number of factors}}{\text{total possible counts}} = \frac{9}{36} = \frac{1}{4}
- Thus, the probability is \(\boxed{\frac{1}{4}}\).
- Question:** Suppose that \( v \) is a positive multiple of 5. If \( v^2 \) is less than 600, what is the greatest possible value of \( v \)?
- We want the largest such \( v \).
- First, solve the inequality:
- v^2 < 600 \Rightarrow v < \sqrt{600}
