P(\text{al menos una negra}) = 1 - \frac{1}{6} = \frac{5}{6}
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- Probabilidad de no extraer canicas negras:
- P(\text{ninguna negra}) = \frac{20}{120} = \frac{1}{6}
- Probabilidad de extraer al menos una canica negra:
- \boxed{\dfrac{5}{6}}
- Pregunta: Chase tiene 5 manzanas, 4 plátanos y 3 cerezas. Si come una pieza de fruta cada día durante 12 días, ¿de cuántas maneras distintas puede consumir todas las frutas?
- Solución: El problema es una permutación de un multiconjunto.
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