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Solution: Let $ y = x^2 - 1 $. Then $ x^2 = y + 1 $. Substitute into $ g(y) = 2x^4 - 5x^2 + 1 $:x^4 = (x^2)^2 = (y + 1)^2 = y^2 + 2y + 1.g(y) = 2(y^2 + 2y + 1) - 5(y + 1) + 1 = 2y^2 + 4y + 2 - 5y - 5 + 1 = 2y^2 - y - 2.Now, substitute $ y = x^2 + 1 $ to find $ g(x^2 + 1) $:g(x^2 + 1) = 2(x^2 + 1)^2 - (x^2 + 1) - 2 = 2x^4 + 4x^2 + 2 - x^2 - 1 - 2 = 2x^4 + 3x^2 - 1.The final answer is $ \boxed{2x^4 + 3x^2 - 1} $.Question: An angel investor analyzes a medical startup's growth, modeled by the polynomial $ g(x) $, where $ g(x^2 + 2) = 3x^6 - 4x^4 + 5x^2 - 2 $. Find $ g(x^2 - 2) $.Solution: Let $ y = x^2 + 2 $. Then $ x^2 = y - 2 $. Express $ g(y) $ in terms of $ y $:g(y) = 3x^6 - 4x^4 + 5x^2 - 2 = 3(x^2)^3 - 4(x^2)^2 + 5x^2 - 2 = 3(y - 2)^3 - 4(y - 2)^2 + 5(y - 2) - 2.3(y^3 - 6y^2 + 12y - 8) - 4(y^2 - 4y + 4) + 5y - 10 - 2 = 3y^3 - 18y^2 + 36y - 24 - 4y^2 + 16y - 16 + 5y - 12 = 3y^3 - 22y^2 + 57y - 52.