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Podemos factorizar $\cos(z)$:
\cos(z)(2\sin(z) - 1) = 0.
Esto nos da dos casos para resolver:
$\cos(z) = 0$
$2\sin(z) - 1 = 0 \implies \sin(z) = \frac{1}{2}$
Caso 1: $\cos(z) = 0$
Las soluciones para $\cos(z) = 0$ en el intervalo $[0^\circ, 360^\circ]$ son:
z = 90^\circ, 270^\circ.
Caso 2: $\sin(z) = \frac{1}{2}$
Las soluciones para $\sin(z) = \frac{1}{2}$ en el intervalo $[0^\circ, 360^\circ]$ son: