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2026 JDG 03 GEN

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2024 MSI GEN 3:1 BLG

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But l unknown.But V = w×h×l = 1,440 m³And dV/dt = 1,440 × (dw/dt × (1/h) + w × (dh/dt)/h)? No.Correct: dV/dt = (dw/dt)(h×l) + (dh/dt)(w×l) + (dw/dt)(dh/dt)×l? No — chain rule gives:dV/dt = ∂V/∂w × dw/dt + ∂V/∂h × dh/dt + ∂V/∂l × dl/dtBut only dl/dt = 4 m/s, others unknown.Assume the length l is constant, so ∂V/∂l independent, but missing rate.Given complexity, assume the volume increase is due to width and height expansion at constant rates, and length constant. But need l.From initial conditions: at current time: V = 1,440, dw/dt = 2, dh/dt = 3, dl/dt = 4But we need dV/dt at this instant: