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- But note: the problem says exactly two of the chosen options are the same — this could be misinterpreted as at least two are the same, but the phrasing exactly two suggests a single pair and the rest different — i.e., one word appears twice, the others appear once — which is standard in such puzzles.
- Thus, our count is correct.
- Hence, the probability is:
- Wait: $144 / 16 = 9$, $256 / 16 = 16$, so yes, $\frac{144}{256} = \frac{9}{16}$? Actually:
- $144 = 16 \times 9$, $256 = 16 \times 16$, yes — so $\frac{144}{256} = \frac{9}{16}$? No: $16 \times 9 = 144$, $16 \times 16 = 256$, so $\frac{144}{256} = \frac{9}{16}$? Wait: $\frac{144}{256} = \frac{144 \div 16}{256 \div 16} = \frac{9}{16}$ — yes, correct.
- But wait: $\frac{9}{16} = 0.5625$, but let’s verify total favorable: