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Home / $-2x^2 = -2(\omega - 1) = -2\omega + 2$

$-2x^2 = -2(\omega - 1) = -2\omega + 2$

February 22, 2026

$-2x^2 = -2(\omega - 1) = -2\omega + 2$

Related Articles

$\omega^3 = \omega \cdot \omega^2 = \omega(\omega - 1) = \omega^2 - \omega = (\omega - 1) - \omega = -1$
$x^4 = -\omega$
$3x^3 = 3(-1) = -3$
$x = \omega$
Constant: +5
$-\omega -3 -2\omega + 2 + \omega + 5 = (-\omega -2\omega + \omega) + (-3 + 2 + 5) = (-2\omega) + 4$

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