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/ $ \log(1.484375) \approx 0.17116 $
$ \log(1.484375) \approx 0.17116 $
February 22, 2026
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#### 4014.41
$ (n-1) \log(1.125) > \log(1.484375) $
$ \log(1.125) \approx 0.051161 $
$ (1.125)^k > 1.484375 $
$ k=4 $: $ 1.423828125 \times 1.125 = 1.60040625 > 1.484375 $
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